新文章測試3
test
test HTML/JavaScript
Hello
https://tw.stock.yahoo.com/#:~:text=%E5%A4%A7%E7%9B%A4%E8%A1%8C%E6%83%85,35264.672026年9月16日 星期三
2026年9月15日 星期二
2021年12月29日 星期三
Maze
m = [
[2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2],
[2,1,0,0,2,0,0,0,2,0,0,0,0,0,2,0,0,0,0,2],
[2,0,0,0,2,0,0,0,2,0,2,2,2,2,2,2,2,2,2,2],
[2,2,2,0,2,2,2,2,2,0,0,0,0,0,2,0,0,0,0,2],
[2,0,0,0,2,0,0,0,2,0,0,2,0,0,2,0,0,0,0,2],
[2,0,2,2,2,2,2,2,2,2,0,2,0,2,2,2,2,2,2,2],
[2,0,2,2,2,2,2,2,2,2,0,2,0,2,2,2,2,2,2,2],
[2,0,0,0,0,0,0,0,2,0,0,2,0,0,0,0,2,0,0,2],
[2,0,0,0,2,0,0,0,2,0,0,2,0,0,2,0,0,0,0,2],
[2,2,2,2,2,2,2,0,2,0,2,2,2,2,2,2,2,0,2,2],
[2,0,0,0,2,0,0,0,2,0,0,2,0,0,0,0,2,0,0,2],
[2,0,0,0,2,0,0,0,0,0,0,2,0,0,0,0,2,0,0,2],
[2,0,0,0,2,0,2,2,2,2,0,2,0,0,0,0,2,0,999,2],
[2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2]
]
for i in m:
print(i)
for i in range(len(m)):
for j in range(len(m[i])):
if m[i][j] == 2: m[i][j] = 200
k = 1
while k<100:
for i in range(len(m)):
for j in range(len(m[i])):
# if m[i][j] == 999:break
if m[i][j] == 0:
t = 0
if m[i][j-1]<200 and m[i][j-1]>t:t = m[i][j-1]
if m[i][j+1]<200 and m[i][j+1]>t:t = m[i][j+1]
if m[i-1][j]<200 and m[i-1][j]>t:t = m[i-1][j]
if m[i+1][j]<200 and m[i+1][j]>t:t = m[i+1][j]
if t == k:m[i][j] = k+1
k = k+1
for i in range(len(m)):
for j in range(len(m[i])):
if m[i][j] == 200: m[i][j] = '#'
for i in m:
for j in i:
print(j,end='\t')
print()
2021年12月26日 星期日
c++ Sort
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
string na[] = {"王一美","林二美","張三美","李四美","王五美"};
int ch[]={95,80,70,60,50};
int en[]={60,70,80,90,93};
int ma[]={60,70,80,90,95};
int tot[5];
float avg[5];
int ord[5];
for (int i=0;i<5;i++)
{
tot[i] = ch[i]+en[i]+ma[i];
avg[i] = (ch[i]*5.0+en[i]*4+ma[i]*3)/12;
avg[i] = floor(avg[i]*10+0.5)/10;
}
for (int i=0;i<5;i++)
{
ord[i] = 1;
for (int j=0;j<5;j++)
if (tot[i]<tot[j])
ord[i]++;
}
cout << "編號"<<" "<< "姓名"<<" "<< "國"<<" "<<"英"<<" "<<"數"<<" "<<"總分"<<" "<<"平均"<<" "<<"名次"<<endl;
for (int i =0 ;i<5;i++)
cout << i+1<<" "<< na[i]<<" "<< ch[i]<<" "<<en[i]<<" "<<ma[i]<<" "<<tot[i]<<" "<<avg[i]<<" "<<ord[i]<<endl;
}